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2x 3 4x 2 8x


Question 663778: Factor the polynomial? 2x^3+4x^2+8x
Answer by jim_thompson5910(35256) About Me (Show Source):

Yous tin can put this solution on YOUR website!

2x%5E3%2B4x%5E2%2B8x Start with the given expression.

2x%28x%5E2%2B2x%2B4%29 Factor out the GCF 2x.

Now permit's try to factor the inner expression x%5E2%2B2x%2B4

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Looking at the expression x%5E2%2B2x%2B4, we can see that the starting time coefficient is 1, the second coefficient is 2, and the last term is 4.

At present multiply the first coefficient 1 past the last term 4 to get %281%29%284%29=4.

At present the question is: what two whole numbers multiply to 4 (the previous production)

and add to the second coefficient 2?

To find these two numbers, we need to list

all of the factors of 4 (the previous product).

Factors of 4:
ane,2,four
-1,-two,-4

Note: list the negative of each factor. This volition allow u.s.a. to find all possible combinations.

These factors pair upwardly and multiply to 4.
1*4 = 4
two*2 = four
(-1)*(-4) = 4
(-two)*(-2) = 4

Now allow's add up each pair of factors to meet if i pair adds to the center coefficient 2:

First Number Second Number Sum
1 4 ane+4=5
2 ii 2+ii=iv
-1 -4 -ane+(-iv)=-5
-2 -2 -2+(-2)=-4

From the table, we can run into that there are no pairs of numbers which add to 2. Then x%5E2%2B2x%2B4 cannot be factored.

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Answer:

So 2x%5E3%2B4x%5E2%2B8x simply factors to 2x%28x%5E2%2B2x%2B4%29

In other words, 2x%5E3%2B4x%5E2%2B8x=2x%28x%5E2%2B2x%2B4%29.


2x 3 4x 2 8x,

Source: https://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/Polynomials-and-rational-expressions.faq.question.663778.html

Posted by: smithshoursted1949.blogspot.com

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